If \[f(x)=5lo{{g}_{5}}x\] then \[{{f}^{-1}}(\alpha -\beta )\] where \[\alpha ,\beta \in R\]is equal to

\[\frac{1}{f(\alpha -\beta )}\]

\[{{f}^{-1}}(\alpha )-{{f}^{-1}}(\beta )\]

\[\frac{{{f}^{-1}}(\alpha )}{{{f}^{-1}}(\beta )}\]

\[\frac{1}{f(\alpha )-f(\beta )}\]

If \[f(x)=5lo{{g}_{5}}x\] then \[{{f}^{-1}}(\alpha -\beta )\] where \[

1.	If \[f(x)=5lo{{g}_{5}}x\] then \[{{f}^{-1}}(\alpha -\beta )\] where \[\alpha ,\beta \in R\]is equal to
A.	\[{{f}^{-1}}(\alpha )-{{f}^{-1}}(\beta )\]
B.	\[\frac{{{f}^{-1}}(\alpha )}{{{f}^{-1}}(\beta )}\]
C.	\[\frac{1}{f(\alpha -\beta )}\]
D.	\[\frac{1}{f(\alpha )-f(\beta )}\]
Answer» C. \[\frac{1}{f(\alpha -\beta )}\]

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If \[f(x)=5lo{{g}_{5}}x\] then \[{{f}^{-1}}(\alpha -\beta )\] where \[\alpha ,\beta \in R\]is equal to

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