If \[f(x)=2\sin x\], \[g(x)={{\cos }^{2}}x\], then \[(f+g)\left( \frac{\pi }{3} \right)=\]

If \[f(x)=2\sin x\], \[g(x)={{\cos }^{2}}x\], then \[(f+g)\left( \frac

1.	If \[f(x)=2\sin x\], \[g(x)={{\cos }^{2}}x\], then \[(f+g)\left( \frac{\pi }{3} \right)=\]
A.	1
B.	\[\frac{2\sqrt{3}+1}{4}\]
C.	\[\sqrt{3}+\frac{1}{4}\]
D.	None of these
Answer» D. None of these

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If \[f(x)=2\sin x\], \[g(x)={{\cos }^{2}}x\], then \[(f+g)\left( \frac{\pi }{3} \right)=\]

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