If \[f({{x}_{1}})-f({{x}_{2}})=f\left( \frac{{{x}_{1}}-{{x}_{2}}}{1-{{x}_{1}}{{x}_{2}}} \right)\] for then what is \[f(x)\] equal to?

\[\ln \left( \frac{2+x}{1-x} \right)\]

\[\ln \left( \frac{1-x}{1+x} \right)\]

\[{{\tan }^{-1}}\left( \frac{1-x}{1+x} \right)\]

\[{{\tan }^{-1}}\left( \frac{1+x}{1-x} \right)\]

If \[f({{x}_{1}})-f({{x}_{2}})=f\left( \frac{{{x}_{1}}-{{x}_{2}}}{1-{{

1.	If \[f({{x}_{1}})-f({{x}_{2}})=f\left( \frac{{{x}_{1}}-{{x}_{2}}}{1-{{x}_{1}}{{x}_{2}}} \right)\] for then what is \[f(x)\] equal to?
A.	\[\ln \left( \frac{1-x}{1+x} \right)\]
B.	\[\ln \left( \frac{2+x}{1-x} \right)\]
C.	\[{{\tan }^{-1}}\left( \frac{1-x}{1+x} \right)\]
D.	\[{{\tan }^{-1}}\left( \frac{1+x}{1-x} \right)\]
Answer» B. \[\ln \left( \frac{2+x}{1-x} \right)\]

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If \[f({{x}_{1}})-f({{x}_{2}})=f\left( \frac{{{x}_{1}}-{{x}_{2}}}{1-{{x}_{1}}{{x}_{2}}} \right)\] for then what is \[f(x)\] equal to?

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