If f is continuous function, then [Kerala (Engg.) 2005]

\[\int_{-3}^{5}{f(x)dx=\int_{-6}^{10}{f(x/2)]dx}}\]

\[\int_{-2}^{2}{f(x)dx=\int_{0}^{2}{[f(x)-f(-x)]dx}}\]

\[\int_{-3}^{5}{2f(x)dx=\int_{-6}^{10}{f(x-1)dx}}\]

\[\int_{-3}^{5}{f(x)dx=\int_{-4}^{4}{f(x-1)dx}}\]

\[\int_{-3}^{5}{f(x)dx=\int_{-2}^{6}{f(x-1)dx}}\]

If f is continuous function, then [Ker

1.	If f is continuous function, then [Kerala (Engg.) 2005]
A.	\[\int_{-2}^{2}{f(x)dx=\int_{0}^{2}{[f(x)-f(-x)]dx}}\]
B.	\[\int_{-3}^{5}{2f(x)dx=\int_{-6}^{10}{f(x-1)dx}}\]
C.	\[\int_{-3}^{5}{f(x)dx=\int_{-4}^{4}{f(x-1)dx}}\]
D.	\[\int_{-3}^{5}{f(x)dx=\int_{-2}^{6}{f(x-1)dx}}\]
E.	\[\int_{-3}^{5}{f(x)dx=\int_{-6}^{10}{f(x/2)]dx}}\]
Answer» E. \[\int_{-3}^{5}{f(x)dx=\int_{-6}^{10}{f(x/2)]dx}}\]

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If f is continuous function, then [Kerala (Engg.) 2005]

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