If \[f(9)=9\], \[f'(9)=4\], then \[\underset{x\to 9}{\mathop{\lim }}\,\frac{\sqrt{f(x)}-3}{\sqrt{x}-3}=\] [IIT 1988; Karnataka CET 1999]

If \[f(9)=9\], \[f'(9)=4\], then \[\underset{x\to 9}{\mathop{\lim }}\,

1.	If \[f(9)=9\], \[f'(9)=4\], then \[\underset{x\to 9}{\mathop{\lim }}\,\frac{\sqrt{f(x)}-3}{\sqrt{x}-3}=\] [IIT 1988; Karnataka CET 1999]
A.	2
B.	4
C.	?2
D.	?4
Answer» C. ?2

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If \[f(9)=9\], \[f'(9)=4\], then \[\underset{x\to 9}{\mathop{\lim }}\,\frac{\sqrt{f(x)}-3}{\sqrt{x}-3}=\] [IIT 1988; Karnataka CET 1999]

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