If degree of dissociation of pure water at\[100{}^\circ C\] is\[1.8\times {{10}^{-8}}\], then the dissociation constant of water will be (density of\[{{H}_{2}}O=1g/cc\])

If degree of dissociation of pure water at\[100{}^\circ C\] is\[1.8\ti

1.	If degree of dissociation of pure water at\[100{}^\circ C\] is\[1.8\times {{10}^{-8}}\], then the dissociation constant of water will be (density of\[{{H}_{2}}O=1g/cc\])
A.	\[1\times {{10}^{-12}}\]
B.	\[1\times {{10}^{-14}}\]
C.	\[1.8\times {{10}^{-12}}\]
D.	\[1.8\times {{10}^{-14}}\]
Answer» E.

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If degree of dissociation of pure water at\[100{}^\circ C\] is\[1.8\times {{10}^{-8}}\], then the dissociation constant of water will be (density of\[{{H}_{2}}O=1g/cc\])

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