If cot \[(\alpha +\beta )=0,\]then \[\sin (\alpha +2\beta )=\] [Kerala (Engg.) 2001]

If cot \[(\alpha +\beta )=0,\]then \[\sin (\alpha +2\beta )=\] [Kerala

1.	If cot \[(\alpha +\beta )=0,\]then \[\sin (\alpha +2\beta )=\] [Kerala (Engg.) 2001]
A.	\[\sin \alpha \]
B.	\[\cos \alpha \]
C.	\[\sin \beta \]
D.	\[\cos 2\beta \]
Answer» B. \[\cos \alpha \]

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If cot \[(\alpha +\beta )=0,\]then \[\sin (\alpha +2\beta )=\] [Kerala (Engg.) 2001]

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