If \[{{\cot }^{-1}}x+{{\tan }^{-1}}3=\frac{\pi }{2}\], then x =

1.	If \[{{\cot }^{-1}}x+{{\tan }^{-1}}3=\frac{\pi }{2}\], then x =
A.	44256
B.	44287
C.	3
D.	4
Answer» D. 4

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If \[{{\cot }^{-1}}x+{{\tan }^{-1}}3=\frac{\pi }{2}\], then x =

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