If \[{{\cot }^{-1}}(\sqrt{\cos \alpha )}-{{\tan }^{-1}}(\sqrt{\cos \alpha })=x\], then sin x is

\[{{\cot }^{2}}\frac{\alpha }{2}\]

\[{{\tan }^{2}}\frac{\alpha }{2}\]

If \[{{\cot }^{-1}}(\sqrt{\cos \alpha )}-{{\tan }^{-1}}(\sqrt{\cos \al

1.	If \[{{\cot }^{-1}}(\sqrt{\cos \alpha )}-{{\tan }^{-1}}(\sqrt{\cos \alpha })=x\], then sin x is
A.	\[{{\tan }^{2}}\frac{\alpha }{2}\]
B.	\[{{\cot }^{2}}\frac{\alpha }{2}\]
C.	\[\tan \alpha \]
D.	\[\cot \frac{\alpha }{2}\]
Answer» B. \[{{\cot }^{2}}\frac{\alpha }{2}\]

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If \[{{\cot }^{-1}}(\sqrt{\cos \alpha )}-{{\tan }^{-1}}(\sqrt{\cos \alpha })=x\], then sin x is

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