If \[{{\cot }^{-1}}\alpha +{{\cot }^{-1}}\beta ={{\cot }^{-1}}x,\]then \[x=\] [MP PET 1992]

\[\frac{1+\alpha \beta }{\alpha +\beta }\]

\[\frac{\alpha \beta -1}{\alpha +\beta }\]

If \[{{\cot }^{-1}}\alpha +{{\cot }^{-1}}\beta ={{\cot }^{-1}}x,\]then

1.	If \[{{\cot }^{-1}}\alpha +{{\cot }^{-1}}\beta ={{\cot }^{-1}}x,\]then \[x=\] [MP PET 1992]
A.	\[\alpha +\beta \]
B.	\[\alpha -\beta \]
C.	\[\frac{1+\alpha \beta }{\alpha +\beta }\]
D.	\[\frac{\alpha \beta -1}{\alpha +\beta }\]
Answer» E.

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If \[{{\cot }^{-1}}\alpha +{{\cot }^{-1}}\beta ={{\cot }^{-1}}x,\]then \[x=\] [MP PET 1992]

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