1.

If\[\cos \,(\theta -\alpha )=a,\,\,\sin \,(\theta -\beta )=b,\,\,\]then \[{{\cos }^{2}}(\alpha -\beta )+2ab\,\sin \,(\alpha -\beta )\] is equal to

A. \[4{{a}^{2}}{{b}^{2}}\]
B. \[{{a}^{2}}-{{b}^{2}}\]
C. \[{{a}^{2}}+{{b}^{2}}\]
D. \[-{{a}^{2}}{{b}^{2}}\]
Answer» D. \[-{{a}^{2}}{{b}^{2}}\]


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