MCQOPTIONS
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| 1. |
If\[\cos \,(\theta -\alpha )=a,\,\,\sin \,(\theta -\beta )=b,\,\,\]then \[{{\cos }^{2}}(\alpha -\beta )+2ab\,\sin \,(\alpha -\beta )\] is equal to |
| A. | \[4{{a}^{2}}{{b}^{2}}\] |
| B. | \[{{a}^{2}}-{{b}^{2}}\] |
| C. | \[{{a}^{2}}+{{b}^{2}}\] |
| D. | \[-{{a}^{2}}{{b}^{2}}\] |
| Answer» D. \[-{{a}^{2}}{{b}^{2}}\] | |