1.

If\[\cos \alpha +\cos \beta =0=sin\alpha +sin\beta ,\]then \[\cos 2\alpha +\cos 2\beta \]is equal to

A. \[-2\sin (\alpha +\beta )\]
B. \[-2\cos (\alpha +\beta )\]
C. \[2\sin (\alpha +\beta )\] 
D. \[2\cos (\alpha +\beta )\]
Answer» C. \[2\sin (\alpha +\beta )\] 


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