If \[\cos (\alpha +\beta )=\frac{4}{5},\sin (\alpha -\beta )=\frac{5}{13}\] and \[\alpha ,\beta \] lie between 0 and \[\frac{\pi }{4},\]then \[\tan 2\alpha =\] [IIT 1979; EAMCET 2002]

If \[\cos (\alpha +\beta )=\frac{4}{5},\sin (\alpha -\beta )=\frac{5}{

1.	If \[\cos (\alpha +\beta )=\frac{4}{5},\sin (\alpha -\beta )=\frac{5}{13}\] and \[\alpha ,\beta \] lie between 0 and \[\frac{\pi }{4},\]then \[\tan 2\alpha =\] [IIT 1979; EAMCET 2002]
A.	\[\frac{16}{63}\]
B.	\[\frac{56}{33}\]
C.	\[\frac{28}{33}\]
D.	None of these
Answer» C. \[\frac{28}{33}\]

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If \[\cos (\alpha +\beta )=\frac{4}{5},\sin (\alpha -\beta )=\frac{5}{13}\] and \[\alpha ,\beta \] lie between 0 and \[\frac{\pi }{4},\]then \[\tan 2\alpha =\] [IIT 1979; EAMCET 2002]

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