If \[\cos 3x+\sin \left( 2x-\frac{7\pi }{6} \right)=-2\], then \[x=\] (where \[k\in Z\])

If \[\cos 3x+\sin \left( 2x-\frac{7\pi }{6} \right)=-2\], then \[x=\]

1.	If \[\cos 3x+\sin \left( 2x-\frac{7\pi }{6} \right)=-2\], then \[x=\] (where \[k\in Z\])
A.	\[\frac{\pi }{3}(6k+1)\]
B.	\[\frac{\pi }{3}(6k+1)\]
C.	\[\frac{\pi }{3}(2k+1)\]
D.	None of these
Answer» B. \[\frac{\pi }{3}(6k+1)\]

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If \[\cos 3x+\sin \left( 2x-\frac{7\pi }{6} \right)=-2\], then \[x=\] (where \[k\in Z\])

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