If \[\cos (2{{\sin }^{-1}}x)=\frac{1}{9},\]then \[x=\] [Roorkee 1975]

1.	If \[\cos (2{{\sin }^{-1}}x)=\frac{1}{9},\]then \[x=\] [Roorkee 1975]
A.	Only 2/3
B.	Only -2/3
C.	2/3, -2/3
D.	Neither 2/3 nor -2/3
Answer» D. Neither 2/3 nor -2/3

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If \[\cos (2{{\sin }^{-1}}x)=\frac{1}{9},\]then \[x=\] [Roorkee 1975]

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