If \[{{\cos }^{-1}}\left( \frac{1}{x} \right)=\theta \], then \[\tan \theta \]= [MNR 1978; MP PET 1989]

\[\frac{1}{\sqrt{{{x}^{2}}-1}}\]

If \[{{\cos }^{-1}}\left( \frac{1}{x} \right)=\theta \], then \[\tan \

1.	If \[{{\cos }^{-1}}\left( \frac{1}{x} \right)=\theta \], then \[\tan \theta \]= [MNR 1978; MP PET 1989]
A.	\[\frac{1}{\sqrt{{{x}^{2}}-1}}\]
B.	\[\sqrt{{{x}^{2}}+1}\]
C.	\[\sqrt{1-{{x}^{2}}}\]
D.	\[\sqrt{{{x}^{2}}-1}\]
Answer» E.

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If \[{{\cos }^{-1}}\left( \frac{1}{x} \right)=\theta \], then \[\tan \theta \]= [MNR 1978; MP PET 1989]

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