MCQOPTIONS
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| 1. |
If \[C=2cos\theta ,\] then the value of the determinant\[\Delta =\left[ \begin{matrix} C & 1 & 0 \\ 1 & C & 1 \\ 6 & 1 & C \\ \end{matrix} \right]\] is |
| A. | \[\frac{2{{\sin }^{2}}2\theta }{\sin \theta }\] |
| B. | \[8{{\cos }^{3}}\theta -4\cos \theta +6\] |
| C. | \[\frac{2\sin 2\theta }{\sin \theta }\] |
| D. | \[8{{\cos }^{3}}\theta +4\cos \theta +6\] |
| Answer» C. \[\frac{2\sin 2\theta }{\sin \theta }\] | |