If \[{{c}^{2}}={{a}^{2}}+{{b}^{2}}\], then \[4s(s-a)(s-b)(s-c)=\] [EAMCET 1986; Pb. CET 1990]

If \[{{c}^{2}}={{a}^{2}}+{{b}^{2}}\], then \[4s(s-a)(s-b)(s-c)=\] [EAM

1.	If \[{{c}^{2}}={{a}^{2}}+{{b}^{2}}\], then \[4s(s-a)(s-b)(s-c)=\] [EAMCET 1986; Pb. CET 1990]
A.	\[{{s}^{4}}\]
B.	\[{{b}^{2}}{{c}^{2}}\]
C.	\[{{c}^{2}}{{a}^{2}}\]
D.	\[{{a}^{2}}{{b}^{2}}\]
Answer» E.

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If \[{{c}^{2}}={{a}^{2}}+{{b}^{2}}\], then \[4s(s-a)(s-b)(s-c)=\] [EAMCET 1986; Pb. CET 1990]

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