If \[b\sin \alpha =a\sin (\alpha +2\beta ),\] then \[\frac{a+b}{a-b}=\

1.	If \[b\sin \alpha =a\sin (\alpha +2\beta ),\] then \[\frac{a+b}{a-b}=\]
A.	\[\frac{\tan \beta }{\tan (\alpha +\beta )}\]
B.	\[\frac{\cot \beta }{\cot (\alpha -\beta )}\]
C.	\[\frac{-\cot \beta }{\cot (\alpha +\beta )}\]
D.	\[\frac{\cot \beta }{\cot (\alpha +\beta )}\]
Answer» D. \[\frac{\cot \beta }{\cot (\alpha +\beta )}\]

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If \[b\sin \alpha =a\sin (\alpha +2\beta ),\] then \[\frac{a+b}{a-b}=\]

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