If ax + by = 1 and bx + ay \(= \frac{{2ab}}{{{a^2}\; + \;{b^2}}}\) th – McqOptions

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1.	If ax + by = 1 and bx + ay \(= \frac{{2ab}}{{{a^2}\; + \;{b^2}}}\) then (x2 + y2)(a2 + b2) is equal to
A.	1
B.	2
C.	0.5
D.	0
Answer» B. 2

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