

MCQOPTIONS
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1. |
If any leap year is selected at random, then the probability of containing 53 Fridays in that year will be |
A. | \(\frac{1}{7}\) |
B. | \(\frac{2}{7}\) |
C. | \(\frac{53}{366}\) |
D. | \(\frac{7}{53}\) |
Answer» C. \(\frac{53}{366}\) | |