If \[\alpha ,\beta \] be the roots of the equation \[2{{x}^{2}}-2({{m}^{2}}+1)x+{{m}^{4}}+{{m}^{2}}+1=0\], then \[{{\alpha }^{2}}+{{\beta }^{2}}\]=

If \[\alpha ,\beta \] be the roots of the equation \[2{{x}^{2}}-2({{m}

1.	If \[\alpha ,\beta \] be the roots of the equation \[2{{x}^{2}}-2({{m}^{2}}+1)x+{{m}^{4}}+{{m}^{2}}+1=0\], then \[{{\alpha }^{2}}+{{\beta }^{2}}\]=
A.	0
B.	1
C.	m
D.	\[{{m}^{2}}\]
Answer» E.

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If \[\alpha ,\beta \] be the roots of the equation \[2{{x}^{2}}-2({{m}^{2}}+1)x+{{m}^{4}}+{{m}^{2}}+1=0\], then \[{{\alpha }^{2}}+{{\beta }^{2}}\]=

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