If \[\alpha ,\beta \] are roots of \[a{{x}^{2}}+bx+b=0,\] then \[\sqrt{\frac{\alpha }{\beta }}+\sqrt{\frac{\beta }{\alpha }}+\sqrt{\frac{b}{a}}\] is (\[{{b}^{2}}\ge 4ab,\] a and b are of same sign)

If \[\alpha ,\beta \] are roots of \[a{{x}^{2}}+bx+b=0,\] then \[\sqrt

1.	If \[\alpha ,\beta \] are roots of \[a{{x}^{2}}+bx+b=0,\] then \[\sqrt{\frac{\alpha }{\beta }}+\sqrt{\frac{\beta }{\alpha }}+\sqrt{\frac{b}{a}}\] is (\[{{b}^{2}}\ge 4ab,\] a and b are of same sign)
A.	0
B.	1
C.	2
D.	\[2\sqrt{\frac{b}{a}}\]
Answer» E.

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If \[\alpha ,\beta \] are roots of \[a{{x}^{2}}+bx+b=0,\] then \[\sqrt{\frac{\alpha }{\beta }}+\sqrt{\frac{\beta }{\alpha }}+\sqrt{\frac{b}{a}}\] is (\[{{b}^{2}}\ge 4ab,\] a and b are of same sign)

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