If \[\alpha \]and \[\beta \] be the roots of the equation \[2{{x}^{2}}+2(a+b)x+{{a}^{2}}+{{b}^{2}}=0\], then the equation whose roots are \[{{(\alpha +\beta )}^{2}}\]and \[{{(\alpha -\beta )}^{2}}\] is

\[{{x}^{2}}-4abx+{{({{a}^{2}}-{{b}^{2}})}^{2}}=0\]

\[{{x}^{2}}-2abx-{{({{a}^{2}}-{{b}^{2}})}^{2}}=0\]

\[{{x}^{2}}-4abx-{{({{a}^{2}}-{{b}^{2}})}^{2}}=0\]

If \[\alpha \]and \[\beta \] be the roots of the equation \[2{{x}^{2

1.	If \[\alpha \]and \[\beta \] be the roots of the equation \[2{{x}^{2}}+2(a+b)x+{{a}^{2}}+{{b}^{2}}=0\], then the equation whose roots are \[{{(\alpha +\beta )}^{2}}\]and \[{{(\alpha -\beta )}^{2}}\] is
A.	\[{{x}^{2}}-2abx-{{({{a}^{2}}-{{b}^{2}})}^{2}}=0\]
B.	\[{{x}^{2}}-4abx-{{({{a}^{2}}-{{b}^{2}})}^{2}}=0\]
C.	\[{{x}^{2}}-4abx+{{({{a}^{2}}-{{b}^{2}})}^{2}}=0\]
D.	None of these
Answer» C. \[{{x}^{2}}-4abx+{{({{a}^{2}}-{{b}^{2}})}^{2}}=0\]

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If \[\alpha \]and \[\beta \] be the roots of the equation \[2{{x}^{2}}+2(a+b)x+{{a}^{2}}+{{b}^{2}}=0\], then the equation whose roots are \[{{(\alpha +\beta )}^{2}}\]and \[{{(\alpha -\beta )}^{2}}\] is

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