If \[ABCDEF\] is regular hexagon, then \[\overrightarrow{AD}\,+\overrightarrow{EB}+\overrightarrow{FC}=\] [Karnataka CET 2002]

If \[ABCDEF\] is regular hexagon, then \[\overrightarrow{AD}\,+\overri

1.	If \[ABCDEF\] is regular hexagon, then \[\overrightarrow{AD}\,+\overrightarrow{EB}+\overrightarrow{FC}=\] [Karnataka CET 2002]
A.	0
B.	\[2\overrightarrow{AB}\]
C.	\[3\overrightarrow{AB}\]
D.	\[4\overrightarrow{AB}\]
Answer» E.

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If \[ABCDEF\] is regular hexagon, then \[\overrightarrow{AD}\,+\overrightarrow{EB}+\overrightarrow{FC}=\] [Karnataka CET 2002]

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