If ABCD is a parallelogram, $$\overrightarrow{AB}=2\,\mathbf{i}+4\,\mathbf{j}-5\,\mathbf{k}$$ and $$\overrightarrow{AD}=\,\mathbf{i}+2\,\mathbf{j}+3\,\mathbf{k},$$ then the unit vector in the direction of BD is [Roorkee 1976]

Question

If ABCD is a parallelogram, $$\overrightarrow{AB}=2\,\mathbf{i}+4\,\mathbf{j}-5\,\mathbf{k}$$ and $$\overrightarrow{AD}=\,\mathbf{i}+2\,\mathbf{j}+3\,\mathbf{k},$$ then the unit vector in the direction of BD is                                                                                                               [Roorkee 1976]

TuteeHUB · Accepted Answer

$$\frac{1}{69}\,(-\mathbf{i}-2\mathbf{j}+8\,\mathbf{k})$$

TuteeHUB · Answer

$$\frac{1}{\sqrt{69}}\,(\mathbf{i}+2\mathbf{j}-8\mathbf{k})$$

TuteeHUB · Answer

$$\frac{1}{69}\,(\mathbf{i}+2\mathbf{j}-8\,\mathbf{k})$$

TuteeHUB · Answer

$$\frac{1}{\sqrt{69}}\,(-\mathbf{i}-2\mathbf{j}+8\mathbf{k})$$

1.	If ABCD is a parallelogram, \[\overrightarrow{AB}=2\,\mathbf{i}+4\,\mathbf{j}-5\,\mathbf{k}\] and \[\overrightarrow{AD}=\,\mathbf{i}+2\,\mathbf{j}+3\,\mathbf{k},\] then the unit vector in the direction of BD is [Roorkee 1976]
A.	\[\frac{1}{\sqrt{69}}\,(\mathbf{i}+2\mathbf{j}-8\mathbf{k})\]
B.	\[\frac{1}{69}\,(\mathbf{i}+2\mathbf{j}-8\,\mathbf{k})\]
C.	\[\frac{1}{\sqrt{69}}\,(-\mathbf{i}-2\mathbf{j}+8\mathbf{k})\]
D.	\[\frac{1}{69}\,(-\mathbf{i}-2\mathbf{j}+8\,\mathbf{k})\]
Answer» D. \[\frac{1}{69}\,(-\mathbf{i}-2\mathbf{j}+8\,\mathbf{k})\]

If ABCD is a parallelogram, \[\overrightarrow{AB}=2\,\mathbf{i}+4\,\mathbf{j}-5\,\mathbf{k}\] and \[\overrightarrow{AD}=\,\mathbf{i}+2\,\mathbf{j}+3\,\mathbf{k},\] then the unit vector in the direction of BD is [Roorkee 1976]

Discussion

No Comment Found

Related MCQs

Reply to Comment