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1. |
If \[a>2b>0\]then the positive value of m for which \[y=mx-b\sqrt{1+{{m}^{2}}}\]is a common tangent to \[{{x}^{2}}+{{y}^{2}}={{b}^{2}}\]and \[{{(x-a)}^{2}}+{{y}^{2}}={{b}^{2}}\], is [IIT Screening 2002] |
A. | \[\frac{2b}{\sqrt{{{a}^{2}}-4{{b}^{2}}}}\] |
B. | \[\frac{\sqrt{{{a}^{2}}-4{{b}^{2}}}}{2b}\] |
C. | \[\frac{2b}{a-2b}\] |
D. | \[\frac{b}{a-2b}\] |
Answer» B. \[\frac{\sqrt{{{a}^{2}}-4{{b}^{2}}}}{2b}\] | |