If \[A={{\tan }^{-1}}x\], then \[\sin 2A=\] [MNR 1988; UPSEAT 2000]

1.	If \[A={{\tan }^{-1}}x\], then \[\sin 2A=\] [MNR 1988; UPSEAT 2000]
A.	\[\frac{2x}{\sqrt{1-{{x}^{2}}}}\]
B.	\[\frac{2x}{1-{{x}^{2}}}\]
C.	\[\frac{2x}{1+{{x}^{2}}}\]
D.	None of these
Answer» D. None of these

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If \[A={{\tan }^{-1}}x\], then \[\sin 2A=\] [MNR 1988; UPSEAT 2000]

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