If a root of the equation \[a{{x}^{2}}+bx+c=0\]be reciprocal of a root of the equation then\[{a}'{{x}^{2}}+{b}'x+{c}'=0\], then [IIT 1968]

\[{{(b{b}'-a{a}')}^{2}}=(c{a}'-b{c}')(a{b}'-b{c}')\]

\[{{(c{c}'-a{a}')}^{2}}=(b{a}'-c{b}')(a{b}'-b{c}')\]

\[{{(c{c}'-a{a}')}^{2}}=(b{a}'+c{b}')(a{b}'+b{c}')\]

If a root of the equation \[a{{x}^{2}}+bx+c=0\]be reciprocal of a root

1.	If a root of the equation \[a{{x}^{2}}+bx+c=0\]be reciprocal of a root of the equation then\[{a}'{{x}^{2}}+{b}'x+{c}'=0\], then [IIT 1968]
A.	\[{{(c{c}'-a{a}')}^{2}}=(b{a}'-c{b}')(a{b}'-b{c}')\]
B.	\[{{(b{b}'-a{a}')}^{2}}=(c{a}'-b{c}')(a{b}'-b{c}')\]
C.	\[{{(c{c}'-a{a}')}^{2}}=(b{a}'+c{b}')(a{b}'+b{c}')\]
D.	None of these
Answer» B. \[{{(b{b}'-a{a}')}^{2}}=(c{a}'-b{c}')(a{b}'-b{c}')\]

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If a root of the equation \[a{{x}^{2}}+bx+c=0\]be reciprocal of a root of the equation then\[{a}'{{x}^{2}}+{b}'x+{c}'=0\], then [IIT 1968]

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