If a plane cuts off intercepts \[OA=a,OB=b,\] \[OC=c\] from the co-ordinate axes, then the area of the triangle \[ABC\]=

\[\frac{1}{2}\sqrt{{{b}^{2}}{{c}^{2}}+{{c}^{2}}{{a}^{2}}+{{a}^{2}}{{b}^{2}}}\]

\[\frac{1}{2}\sqrt{{{(b-c)}^{2}}+{{(c-a)}^{2}}+{{(a-b)}^{2}}}\]

If a plane cuts off intercepts \[OA=a,OB=b,\] \[OC=c\] from the co-ord

1.	If a plane cuts off intercepts \[OA=a,OB=b,\] \[OC=c\] from the co-ordinate axes, then the area of the triangle \[ABC\]=
A.	\[\frac{1}{2}\sqrt{{{b}^{2}}{{c}^{2}}+{{c}^{2}}{{a}^{2}}+{{a}^{2}}{{b}^{2}}}\]
B.	\[\frac{1}{2}(bc+ca+ab)\]
C.	\[\frac{1}{2}abc\]
D.	\[\frac{1}{2}\sqrt{{{(b-c)}^{2}}+{{(c-a)}^{2}}+{{(a-b)}^{2}}}\]
Answer» B. \[\frac{1}{2}(bc+ca+ab)\]

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If a plane cuts off intercepts \[OA=a,OB=b,\] \[OC=c\] from the co-ordinate axes, then the area of the triangle \[ABC\]=

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