If \[{{a}_{n}}=2n+1\] and \[{{C}_{r}}={{\,}^{n}}{{C}_{r}}\] then\[{{a}_{0}}C_{0}^{2}+{{a}_{1}}C_{1}^{2}+{{a}_{2}}C_{2}^{2}+........{{a}_{n}}C_{n}^{2}=\]

If \[{{a}_{n}}=2n+1\] and \[{{C}_{r}}={{\,}^{n}}{{C}_{r}}\] then\[{{a}

1.	If \[{{a}_{n}}=2n+1\] and \[{{C}_{r}}={{\,}^{n}}{{C}_{r}}\] then\[{{a}_{0}}C_{0}^{2}+{{a}_{1}}C_{1}^{2}+{{a}_{2}}C_{2}^{2}+........{{a}_{n}}C_{n}^{2}=\]
A.	\[(n-1){{(}^{2n}}{{C}_{n}})\]
B.	\[n{{(}^{2n}}{{C}_{n}})\]
C.	\[(n+1){{(}^{2n}}{{C}_{n}})\]
D.	\[(n+1){{(}^{n}}{{C}_{n/2}})\]
Answer» D. \[(n+1){{(}^{n}}{{C}_{n/2}})\]

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If \[{{a}_{n}}=2n+1\] and \[{{C}_{r}}={{\,}^{n}}{{C}_{r}}\] then\[{{a}_{0}}C_{0}^{2}+{{a}_{1}}C_{1}^{2}+{{a}_{2}}C_{2}^{2}+........{{a}_{n}}C_{n}^{2}=\]

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