If A=\[{{\mathbf{2}}^{x}}\], B= \[{{\mathbf{4}}^{y}}\]c=\[{{\mathbf{8}}^{z}}\] where x=\[\mathbf{0}.\overline{\mathbf{1}}\], \[\mathbf{y}=\mathbf{0}.\overline{\mathbf{4}},\mathbf{z}=\mathbf{0}.\overline{\mathbf{6}},\]then \[\mathbf{A}\times \mathbf{B}\times \mathbf{C}\] is

• A. 8
• B. 2
• C. 16
• D. 4