If \[A=\left[ \begin{matrix} 1 & \tan x \\ -\tan x & 1 \\ \end{matrix} \right]\], then \[{{A}^{T}}{{A}^{-1}}\]is

\[\left[ \begin{matrix} \cos 2x & \cos 2x \\ \sin 2x & \sin 2x \\ \end{matrix} \right]\]

\[\left[ \begin{matrix} -\cos 2x & \sin 2x \\ -\sin 2x & \cos 2x \\ \end{matrix} \right]\]

\[\left[ \begin{matrix} \cos 2x & -\sin 2x \\ \sin 2x & \cos 2x \\ \end{matrix} \right]\]

If \[A=\left[ \begin{matrix} 1 & \tan x \\ -\tan x & 1 \

1.	If \[A=\left[ \begin{matrix} 1 & \tan x \\ -\tan x & 1 \\ \end{matrix} \right]\], then \[{{A}^{T}}{{A}^{-1}}\]is
A.	\[\left[ \begin{matrix} -\cos 2x & \sin 2x \\ -\sin 2x & \cos 2x \\ \end{matrix} \right]\]
B.	\[\left[ \begin{matrix} \cos 2x & -\sin 2x \\ \sin 2x & \cos 2x \\ \end{matrix} \right]\]
C.	\[\left[ \begin{matrix} \cos 2x & \cos 2x \\ \sin 2x & \sin 2x \\ \end{matrix} \right]\]
D.	none of these
Answer» C. \[\left[ \begin{matrix} \cos 2x & \cos 2x \\ \sin 2x & \sin 2x \\ \end{matrix} \right]\]

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If \[A=\left[ \begin{matrix} 1 & \tan x \\ -\tan x & 1 \\ \end{matrix} \right]\], then \[{{A}^{T}}{{A}^{-1}}\]is

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