If \[{{A}^{k}}=0\] (A is nilpotent with index k),\[{{(I-A)}^{p}}=I+A+{{A}^{2}}+....+{{A}^{k-1}},\] thus p is,

If \[{{A}^{k}}=0\] (A is nilpotent with index k),\[{{(I-A)}^{p}}=I+A+{

1.	If \[{{A}^{k}}=0\] (A is nilpotent with index k),\[{{(I-A)}^{p}}=I+A+{{A}^{2}}+....+{{A}^{k-1}},\] thus p is,
A.	-1
B.	-2
C.	½
D.	None of these
Answer» B. -2

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If \[{{A}^{k}}=0\] (A is nilpotent with index k),\[{{(I-A)}^{p}}=I+A+{{A}^{2}}+....+{{A}^{k-1}},\] thus p is,

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