If \[(a+ib)(c+id)(e+if)(g+ih)=A+iB,\] then \[({{a}^{2}}+{{b}^{2}})({{c}^{2}}+{{d}^{2}})({{e}^{2}}+{{f}^{2}})({{g}^{2}}+{{h}^{2}})=\]

If \[(a+ib)(c+id)(e+if)(g+ih)=A+iB,\] then \[({{a}^{2}}+{{b}^{2}})({{c

1.	If \[(a+ib)(c+id)(e+if)(g+ih)=A+iB,\] then \[({{a}^{2}}+{{b}^{2}})({{c}^{2}}+{{d}^{2}})({{e}^{2}}+{{f}^{2}})({{g}^{2}}+{{h}^{2}})=\]
A.	\[{{A}^{2}}+{{B}^{2}}\]
B.	\[{{A}^{2}}-{{B}^{2}}\]
C.	\[{{A}^{2}}\]
D.	\[{{B}^{2}}\]
Answer» B. \[{{A}^{2}}-{{B}^{2}}\]

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If \[(a+ib)(c+id)(e+if)(g+ih)=A+iB,\] then \[({{a}^{2}}+{{b}^{2}})({{c}^{2}}+{{d}^{2}})({{e}^{2}}+{{f}^{2}})({{g}^{2}}+{{h}^{2}})=\]

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