If $$a = \frac{{\sqrt 3+ \sqrt 2 }}{{\sqrt 3- \sqrt 2 }},$$$$b = \frac{{\sqrt 3- \sqrt 2 }}{{\sqrt 3+ \sqrt 2 }}$$then the value of $${a^2} + {b^2}$$would be = ?

If $$a = \frac{{\sqrt 3+ \sqrt 2 }}{{\sqrt 3- \sqrt 2 }},$$$$b = \frac

1.	If $$a = \frac{{\sqrt 3+ \sqrt 2 }}{{\sqrt 3- \sqrt 2 }},$$$$b = \frac{{\sqrt 3- \sqrt 2 }}{{\sqrt 3+ \sqrt 2 }}$$then the value of $${a^2} + {b^2}$$would be = ?
A.	0
B.	8
C.	9
D.	00
Answer» C. 9