If\[A=\frac{9{{x}^{4}}-3{{x}^{3}}-6{{x}^{2}}-9x}{3x},\] \[B=\frac{18{{x}^{4}}+12{{x}^{3}}+6{{x}^{2}}+9x}{3x}\]then \[B-A\] is

If\[A=\frac{9{{x}^{4}}-3{{x}^{3}}-6{{x}^{2}}-9x}{3x},\] \[B=\frac{18{{

1.	If\[A=\frac{9{{x}^{4}}-3{{x}^{3}}-6{{x}^{2}}-9x}{3x},\] \[B=\frac{18{{x}^{4}}+12{{x}^{3}}+6{{x}^{2}}+9x}{3x}\]then \[B-A\] is
A.	\[3{{x}^{2}}-5{{x}^{2}}-4x+6\]
B.	\[3{{x}^{3}}+5{{x}^{2}}+4x+6\]
C.	\[3{{x}^{3}}-5{{x}^{2}}-4x-6\]
D.	\[3{{x}^{3}}+5{{x}^{2}}-4x-6\]
Answer» C. \[3{{x}^{3}}-5{{x}^{2}}-4x-6\]