If \[a=\cos \,\theta +i\,\sin \,\theta ,\] then \[\frac{1+a}{1-a}=\] [Karnataka CET 2000]

If \[a=\cos \,\theta +i\,\sin \,\theta ,\] then \[\frac{1+a}{1-a}=\] [

1.	If \[a=\cos \,\theta +i\,\sin \,\theta ,\] then \[\frac{1+a}{1-a}=\] [Karnataka CET 2000]
A.	\[\cot \theta \]
B.	\[\cot \frac{\theta }{2}\]
C.	\[i\,\cot \frac{\theta }{2}\]
D.	\[i\,\tan \frac{\theta }{2}\]
Answer» D. \[i\,\tan \frac{\theta }{2}\]

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If \[a=\cos \,\theta +i\,\sin \,\theta ,\] then \[\frac{1+a}{1-a}=\] [Karnataka CET 2000]

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