MCQOPTIONS
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| 1. |
If a compound on analysis was found to contain C = 18.5%, H = 1.55%, Cl = 55.04% and O = 24.81%, then its empirical formula is [AIIMS 1998] |
| A. | \[CHClO\] |
| B. | \[C{{H}_{2}}ClO\] |
| C. | \[{{C}_{2}}{{H}_{2}}OCl\] |
| D. | \[ClC{{H}_{2}}O\] |
| Answer» B. \[C{{H}_{2}}ClO\] | |