1.

If a compound on analysis was found to contain C = 18.5%, H = 1.55%, Cl = 55.04% and O = 24.81%, then its empirical formula is [AIIMS 1998]

A. \[CHClO\]
B. \[C{{H}_{2}}ClO\]
C. \[{{C}_{2}}{{H}_{2}}OCl\]
D. \[ClC{{H}_{2}}O\]
Answer» B. \[C{{H}_{2}}ClO\]


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