MCQOPTIONS
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| 1. |
If a,b,c are three non-zero, non-coplanar vectors and \[{{b}_{1}}=b-\frac{b.a}{|a{{|}^{2}}}a,\,{{b}_{2}}=b+\frac{b.a}{|a{{|}^{2}}}a\],\[{{c}_{1}}=c-\frac{c.a}{|a{{|}^{2}}}a-\frac{c.b}{|b{{|}^{2}}}b\], \[{{c}_{2}}=c-\frac{c.a}{|a{{|}^{2}}}a\frac{c.{{b}_{1}}}{|{{b}_{1}}{{|}^{2}}}{{b}_{1}}\], \[{{c}_{3}}=c-\frac{c.a}{|a{{|}^{2}}}a\frac{c.{{b}_{2}}}{|{{b}_{2}}{{|}^{2}}}{{b}_{2}}\], \[{{c}_{4}}=a-\frac{c.a}{|a{{|}^{2}}}a\]. Then which of the following is a set of mutually orthogonal vectors is [IIT Screening 2005] |
| A. | \[\{\mathbf{a},\,{{\mathbf{b}}_{1}},\,{{c}_{1}}\}\] |
| B. | \[\{\mathbf{a},\,{{\mathbf{b}}_{1}},\,{{c}_{2}}\}\] |
| C. | \[\{\mathbf{a},\,{{\mathbf{b}}_{2}},\,{{c}_{3}}\}\] |
| D. | \[\{\mathbf{a},\,{{\mathbf{b}}_{2}},\,{{c}_{4}}\}\] |
| Answer» C. \[\{\mathbf{a},\,{{\mathbf{b}}_{2}},\,{{c}_{3}}\}\] | |