If \[a,\ b,\ c\] are in A.P., then \[\frac{{{(a-c)}^{2}}}{({{b}^{2}}-ac)}=\] [Roorkee 1975]

If \[a,\ b,\ c\] are in A.P., then \[\frac{{{(a-c)}^{2}}}{({{b}^{2}}-a

1.	If \[a,\ b,\ c\] are in A.P., then \[\frac{{{(a-c)}^{2}}}{({{b}^{2}}-ac)}=\] [Roorkee 1975]
A.	1
B.	2
C.	3
D.	4
Answer» E.

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If \[a,\ b,\ c\] are in A.P., then \[\frac{{{(a-c)}^{2}}}{({{b}^{2}}-ac)}=\] [Roorkee 1975]

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