If A and B are two events such that \[P\,(A)\ne 0\] and \[P\,(B)\ne 1,\] then \[P\,\left( \frac{{\bar{A}}}{{\bar{B}}} \right)=\] [IIT 1982; RPET 1995, 2000; DCE 2000; UPSEAT 2001]

\[\frac{P\,(\bar{A})}{P\,(\bar{B})}\]

\[1-P\,\left( \frac{A}{B} \right)\]

\[1-P\,\left( \frac{{\bar{A}}}{B} \right)\]

\[\frac{1-P\,(A\cup B)}{P\,(\bar{B})}\]

If A and B are two events such that \[P\,(A)\ne 0\] and \[P\,(B)\ne 1,

1.	If A and B are two events such that \[P\,(A)\ne 0\] and \[P\,(B)\ne 1,\] then \[P\,\left( \frac{{\bar{A}}}{{\bar{B}}} \right)=\] [IIT 1982; RPET 1995, 2000; DCE 2000; UPSEAT 2001]
A.	\[1-P\,\left( \frac{A}{B} \right)\]
B.	\[1-P\,\left( \frac{{\bar{A}}}{B} \right)\]
C.	\[\frac{1-P\,(A\cup B)}{P\,(\bar{B})}\]
D.	\[\frac{P\,(\bar{A})}{P\,(\bar{B})}\]
Answer» D. \[\frac{P\,(\bar{A})}{P\,(\bar{B})}\]

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If A and B are two events such that \[P\,(A)\ne 0\] and \[P\,(B)\ne 1,\] then \[P\,\left( \frac{{\bar{A}}}{{\bar{B}}} \right)=\] [IIT 1982; RPET 1995, 2000; DCE 2000; UPSEAT 2001]

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