If A and B are square matrices of the same order and A is nonsingular, then for a positive integer n, \[{{({{A}^{-1}}BA)}^{n}}\] is equal

\[{{A}^{-n}}{{B}^{n}}{{A}^{n}}\]

\[{{A}^{n}}{{B}^{n}}{{A}^{-n}}\]

If A and B are square matrices of the same order and A is nonsingular,

1.	If A and B are square matrices of the same order and A is nonsingular, then for a positive integer n, \[{{({{A}^{-1}}BA)}^{n}}\] is equal
A.	\[{{A}^{-n}}{{B}^{n}}{{A}^{n}}\]
B.	\[{{A}^{n}}{{B}^{n}}{{A}^{-n}}\]
C.	\[{{A}^{-1}}{{B}^{n}}A\]
D.	\[n({{A}^{-1}}BA)\]
Answer» D. \[n({{A}^{-1}}BA)\]

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If A and B are square matrices of the same order and A is nonsingular, then for a positive integer n, \[{{({{A}^{-1}}BA)}^{n}}\] is equal

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