If a and b are roots of \[{{x}^{2}}-px+q=0\], then \[\frac{1}{a}+\frac{1}{b}=\] [Orissa JEE 2004]

If a and b are roots of \[{{x}^{2}}-px+q=0\], then \[\frac{1}{a}+\frac

1.	If a and b are roots of \[{{x}^{2}}-px+q=0\], then \[\frac{1}{a}+\frac{1}{b}=\] [Orissa JEE 2004]
A.	\[\frac{1}{p}\]
B.	\[\frac{1}{q}\]
C.	\[\frac{1}{2p}\]
D.	\[\frac{p}{q}\]
Answer» E.

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If a and b are roots of \[{{x}^{2}}-px+q=0\], then \[\frac{1}{a}+\frac{1}{b}=\] [Orissa JEE 2004]

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