If \[{{a}^{2}}+{{b}^{2}}+{{c}^{2}}\ne -2\] and\[f(x)=\left| \begin{matrix} (1+{{a}^{2}})x & (1+{{b}^{2}})x & (1+{{c}^{2}})x \\ (1+{{a}^{2}})x & (1+{{b}^{2}})x & (1+{{c}^{2}})x \\ (1+{{a}^{2}})x & (1+{{b}^{2}})x & (1+{{c}^{2}})x \\ \end{matrix} \right|\]then \[f(x)\] is a polynomial of degree

If \[{{a}^{2}}+{{b}^{2}}+{{c}^{2}}\ne -2\] and\[f(x)=\left| \begin{mat

1.	If \[{{a}^{2}}+{{b}^{2}}+{{c}^{2}}\ne -2\] and\[f(x)=\left\| \begin{matrix} (1+{{a}^{2}})x & (1+{{b}^{2}})x & (1+{{c}^{2}})x \\ (1+{{a}^{2}})x & (1+{{b}^{2}})x & (1+{{c}^{2}})x \\ (1+{{a}^{2}})x & (1+{{b}^{2}})x & (1+{{c}^{2}})x \\ \end{matrix} \right\|\]then \[f(x)\] is a polynomial of degree
A.	\[1\]
B.	0
C.	\[3\]
D.	\[2\]
Answer» E.

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If \[{{a}^{2}}+{{b}^{2}}+{{c}^{2}}\ne -2\] and\[f(x)=\left| \begin{matrix} (1+{{a}^{2}})x & (1+{{b}^{2}})x & (1+{{c}^{2}})x \\ (1+{{a}^{2}})x & (1+{{b}^{2}})x & (1+{{c}^{2}})x \\ (1+{{a}^{2}})x & (1+{{b}^{2}})x & (1+{{c}^{2}})x \\ \end{matrix} \right|\]then \[f(x)\] is a polynomial of degree

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