If \[{{a}_{1}},{{a}_{2}}....{{a}_{n}}\]are in H.P., then the expression \[{{a}_{1}}{{a}_{2}}+{{a}_{2}}{{a}_{3}}\]+...+\[{{a}_{n}}{{-}_{1}}{{a}_{n}}\]is equal to

If \[{{a}_{1}},{{a}_{2}}....{{a}_{n}}\]are in H.P., then the expressio

1.	If \[{{a}_{1}},{{a}_{2}}....{{a}_{n}}\]are in H.P., then the expression \[{{a}_{1}}{{a}_{2}}+{{a}_{2}}{{a}_{3}}\]+...+\[{{a}_{n}}{{-}_{1}}{{a}_{n}}\]is equal to
A.	\[n({{a}_{1}}-{{a}_{n}})\]
B.	\[(n-1)({{a}_{1}}-{{a}_{n}})\]
C.	\[n{{a}_{1}}{{a}_{n}}\]
D.	\[(n-1){{a}_{1}}{{a}_{n}}\]
Answer» E.

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If \[{{a}_{1}},{{a}_{2}}....{{a}_{n}}\]are in H.P., then the expression \[{{a}_{1}}{{a}_{2}}+{{a}_{2}}{{a}_{3}}\]+...+\[{{a}_{n}}{{-}_{1}}{{a}_{n}}\]is equal to

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