MCQOPTIONS
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| 1. |
If \[{{a}_{1}},{{a}_{2}},{{a}_{3}},....{{a}_{n}}\] is an \[A.P.\] with common difference d; \[(d>0)\] then \[\tan \left[ {{\tan }^{-1}}\left( \frac{d}{1+{{a}_{1}}{{a}_{2}}} \right)+{{\tan }^{-1}}\left( \frac{d}{1+{{a}_{2}}{{a}_{3}}} \right)+...+ta{{n}^{-1}}\left( \frac{d}{1+{{a}_{n-1}}{{a}_{n}}} \right) \right]\]is equal to |
| A. | \[\frac{(n-1)d}{{{a}_{1}}+{{a}_{n}}}\] |
| B. | \[\frac{(n-1)d}{1+{{a}_{1}}{{a}_{n}}}\] |
| C. | \[\frac{nd}{1+{{a}_{1}}{{a}_{n}}}\] |
| D. | \[\frac{{{a}_{n}}-{{a}_{1}}}{{{a}_{n}}+{{a}_{1}}}\] |
| Answer» C. \[\frac{nd}{1+{{a}_{1}}{{a}_{n}}}\] | |