If \[{{a}_{1}},{{a}_{2}},{{a}_{3}}....{{a}_{n}}\]are in H.P. and \[f(k)=\left( \sum\limits_{r=1}^{n}{{{a}_{r}}} \right)-{{a}_{k}}\]then \[\frac{{{a}_{1}}}{f(1)},\frac{{{a}_{2}}}{f(2)},\frac{{{a}_{3}}}{f(3)},...\frac{{{a}_{n}}}{f(n)}\]are in

If \[{{a}_{1}},{{a}_{2}},{{a}_{3}}....{{a}_{n}}\]are in H.P. and \[f(k

1.	If \[{{a}_{1}},{{a}_{2}},{{a}_{3}}....{{a}_{n}}\]are in H.P. and \[f(k)=\left( \sum\limits_{r=1}^{n}{{{a}_{r}}} \right)-{{a}_{k}}\]then \[\frac{{{a}_{1}}}{f(1)},\frac{{{a}_{2}}}{f(2)},\frac{{{a}_{3}}}{f(3)},...\frac{{{a}_{n}}}{f(n)}\]are in
A.	A.P
B.	G.P
C.	H.P
D.	none of these
Answer» D. none of these

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If \[{{a}_{1}},{{a}_{2}},{{a}_{3}}....{{a}_{n}}\]are in H.P. and \[f(k)=\left( \sum\limits_{r=1}^{n}{{{a}_{r}}} \right)-{{a}_{k}}\]then \[\frac{{{a}_{1}}}{f(1)},\frac{{{a}_{2}}}{f(2)},\frac{{{a}_{3}}}{f(3)},...\frac{{{a}_{n}}}{f(n)}\]are in

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