If \[{{a}_{1}},{{a}_{2}},{{a}_{3}},{{a}_{4}}\] are the coefficients of any four consecutive terms in the expansion of \[{{(1+x)}^{n}}\], then \[\frac{{{a}_{1}}}{{{a}_{1}}+{{a}_{2}}}+\frac{{{a}_{3}}}{{{a}_{3}}+{{a}_{4}}}\] = [IIT 1975]

\[\frac{2{{a}_{3}}}{{{a}_{2}}+{{a}_{3}}}\]

\[\frac{{{a}_{2}}}{{{a}_{2}}+{{a}_{3}}}\]

\[\frac{1}{2}\frac{{{a}_{2}}}{({{a}_{2}}+{{a}_{3}})}\]

\[\frac{2{{a}_{2}}}{{{a}_{2}}+{{a}_{3}}}\]

If \[{{a}_{1}},{{a}_{2}},{{a}_{3}},{{a}_{4}}\] are the coefficients of

1.	If \[{{a}_{1}},{{a}_{2}},{{a}_{3}},{{a}_{4}}\] are the coefficients of any four consecutive terms in the expansion of \[{{(1+x)}^{n}}\], then \[\frac{{{a}_{1}}}{{{a}_{1}}+{{a}_{2}}}+\frac{{{a}_{3}}}{{{a}_{3}}+{{a}_{4}}}\] = [IIT 1975]
A.	\[\frac{{{a}_{2}}}{{{a}_{2}}+{{a}_{3}}}\]
B.	\[\frac{1}{2}\frac{{{a}_{2}}}{({{a}_{2}}+{{a}_{3}})}\]
C.	\[\frac{2{{a}_{2}}}{{{a}_{2}}+{{a}_{3}}}\]
D.	\[\frac{2{{a}_{3}}}{{{a}_{2}}+{{a}_{3}}}\]
Answer» D. \[\frac{2{{a}_{3}}}{{{a}_{2}}+{{a}_{3}}}\]

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If \[{{a}_{1}},{{a}_{2}},{{a}_{3}},{{a}_{4}}\] are the coefficients of any four consecutive terms in the expansion of \[{{(1+x)}^{n}}\], then \[\frac{{{a}_{1}}}{{{a}_{1}}+{{a}_{2}}}+\frac{{{a}_{3}}}{{{a}_{3}}+{{a}_{4}}}\] = [IIT 1975]

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