If \[a=(1,\,-1,\,2),\ b=(-2,\,3,\,5)\], \[\mathbf{c}=(2\,,\,-2,\,4)\] and i is the unit vector in the x-direction, then \[(a-2b+3c)\,.\,i=\] [Karnataka CET 2001]

If \[a=(1,\,-1,\,2),\ b=(-2,\,3,\,5)\], \[\mathbf{c}=(2\,,\,-2,\,4)\]

1.	If \[a=(1,\,-1,\,2),\ b=(-2,\,3,\,5)\], \[\mathbf{c}=(2\,,\,-2,\,4)\] and i is the unit vector in the x-direction, then \[(a-2b+3c)\,.\,i=\] [Karnataka CET 2001]
A.	11
B.	15
C.	18
D.	36
Answer» B. 15

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If \[a=(1,\,-1,\,2),\ b=(-2,\,3,\,5)\], \[\mathbf{c}=(2\,,\,-2,\,4)\] and i is the unit vector in the x-direction, then \[(a-2b+3c)\,.\,i=\] [Karnataka CET 2001]

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